Poll

How did the money arrive on Tena Bar

River Flooding
1 (5%)
Floated to it's resting spot via Columbia river
2 (10%)
Planted
6 (30%)
Dredge
11 (55%)
tossed in the river in a paper bag
0 (0%)

Total Members Voted: 17

Voting closed: August 16, 2016, 09:05:28 AM

Author Topic: Tena Bar Money Find  (Read 1358081 times)

georger

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Re: Tina Bar Money Find
« Reply #525 on: January 11, 2015, 11:51:13 PM »
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I'm including a map showing the location of the path (blue line) you can see it barely reaches the tip of Hayden island. the green line is V-23, and the straight red line is the distance from the path to Smith lake which is a little over 3 miles, or 2.62 Nautical miles. the map was made by Snowmman

It's a little too far west to have hit this water hole. the odds are greater for the Columbia where the plane obviously crossed. Smith lake is surrounded by rivers, why pick this area? why exclude surrounding waters?

This is of course if the path is correct. even if I give an error of .5, it still can't reach the area.... 8)

It's a safe bet to assume Cooper could not see any specific target under the conditions that night so may have aimed for a general area based on some general perception of lights he was seeing ahead, or under him?
 

georger

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Re: Tina Bar Money Find
« Reply #526 on: January 12, 2015, 12:02:23 AM »
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I'm including a map showing the location of the path (blue line) you can see it barely reaches the tip of Hayden island. the green line is V-23, and the straight red line is the distance from the path to Smith lake which is a little over 3 miles, or 2.62 Nautical miles. the map was made by Snowmman

It's a little too far west to have hit this water hole. the odds are greater for the Columbia where the plane obviously crossed. Smith lake is surrounded by rivers, why pick this area? why exclude surrounding waters?

This is of course if the path is correct. even if I give an error of .5, it still can't reach the area.... 8)

I did see Snowmmans map. He has the waypoints marked with straight lines in between, not the actual path, the path in between the waypoints is likely smoothed in reality, as the black line on the FBI map is. Note the black line and green one on the FBI/Snowmman map above differ. There is no actual flight path data in between. But it is reasonable to assume the black line is more likely. It looks like it came close to or over the I5 on Haydon Is, but we just don't know exactly where it was in between those two waypoints. If you smooth the path it puts the plane about 1.25 - 1.5 miles from Smith Lake, within the distance for a no pull landing (on paper). I don't mean to exclude surrounding waters.  Nash's Game Theory,, don't go for the Blonde.

Smith Lake is a significantly large body of water, if flooded in 71, wider than the Columbia is across
I can't find this theory explored previously, unless someone has info
It explains a possible delayed/partial deposit on TBAR
Evidence might still be there. Unlikely if he landed in the Columbia

Any abandoned vehicles around there in 71,, parking tickets issued.. maybe he had a getaway car stashed..

I assume you have read the Dawson article? There has been no previous discussion of Smith Lake.

You have a route and current forces in hand to explain a trip between Smith Lake and T_Bar - unless dredging spoils or construction materials from Hayden Isle or Smith Lake were dumped near Tina Bar ?     

It was Farflung who suggested construction on Hayden or Govt Island might be responsible for the Coopermoney being see free to drift to Tina Bar ???
« Last Edit: January 12, 2015, 12:22:16 AM by georger »
 

Robert99

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Re: Tina Bar Money Find
« Reply #527 on: January 12, 2015, 12:33:41 AM »
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so, if there was a no pull jump at say 20:17:30 between the waypoints, on the black path, close to I5 on Hayden, as the path turned south, a 200lb object would travel for 26 seconds and 1.24 miles straight at Smith Lake. I know these maps are not great and the position between the waypoints is an extrapolation.

It looks like about 1.5 miles..


The release of the NWA papers to the WSHM a few months back indicates that the airliner was actually at Tualatin at 8:18 PM PST.  That point is 25 DME miles (nautical miles) from what is now the Battleground VORTAC and about 14 DME miles further south than the point indicated on your attached map for 8:18.

The paper copy of that report was transmitted through the ARINC teletypewriter system and time stamped at 8:22 PM.  The voice call from the airliner to the ARINC system was patched through to the NWA office at SEA and one report indicates it was actually made at 8:18 PM which fits the overall situation much better.

Interesting, I was just indicating the south turn in the flight path on the map. Is there an issue with the flight path near I5 and Hayden Island between the points?

In order for the airliner to be at the 25 DME mile point south of the present day Battleground VORTAC at 8:18 PM (as it said it was), it would have to take a direct short cut from about Toledo to that point.  That means it would bypass Portland on the west side and fly almost directly over Tina Bar.  I don't think the flight crew would fly over Portland under any circumstances with a bomb on board and a warning from the FAA Chief Psychologist that Cooper would probably blow up the airliner when he jumped.

Isn't this exactly what Dawson said the path was - straight line btwn Toledo and the tip of Hayden Island ?

It would actually be about a mile or two west of the tip of Hayden Island.  The airliner would be going almost straight south (178 degrees true) on that segment.  But Dawson's statement is accurate enough for me under the circumstances.  We just need more accurate data to pin this down exactly.
« Last Edit: January 12, 2015, 12:38:49 AM by Robert99 »
 

FLYJACK

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Re: Tina Bar Money Find
« Reply #528 on: January 12, 2015, 12:37:06 AM »
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The distance from the tip of Hayden to I5 is approx. 1.3 miles. the plane doesn't cross I5 until it's too late for the Smith lake landing. the distance from I5 to Smith lake is approx. 1.3 miles.

It's a possibility, but the odds are low if you go by the map. the black lines where made by the FBI, and the green is what Sluggo copied over if I'm correct.

If we go by Carr stating they claimed the bump was felt around 5-10 minutes after the last contact with Cooper which was 8:05. this gives a time frame of no later than 8:15.

No cars were left at any airports. I believe they covered that. we have no proof Cooper knew where he was. that's the difference between Cooper, and McCoy. Cooper never asked anything about altitude, wind, location, nothing. McCoy stayed on top of things like he was a co-pilot. 

The area in question is a National Preserve. one can expect people around often. if Cooper was at the bottom, or the money was at the bottom. I doubt the flooding would cause it to surface. odds are low again that it was lying around the area waiting to be moved by a flood?

Snowmmans map is direct lines connecting the waypoints, it is not the actual flightpath, it would have been smoother taking it closer to I5.. Was it close enough??? IDK we don't have data in between the waypoints. It looks real close. Smith Lake was intentionally flooded "closed" in the winter and released in the summer. It likely had the high water level in the winter, but I am trying to get info for '71. The Willamette slough flows in and out (controlled) or did. The lake edges are not really explorable by foot, it is a wetland/marsh explorable by canoe. The shoreline is really not well explored.. Anybody have a spare cadaver dog handy and a canoe,,, j/k

If a body did impact a marsh, I am sure it would be buried in the bottom. It isn't very deep. The rotting/movement or yearly flood/release process could loosen some money. About a 6 mile float to TBAR. YES, this is theoretical.. so far

video
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Are there any pilots that can comment on the potential flight path between those waypoints..
 

Robert99

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Re: Tina Bar Money Find
« Reply #529 on: January 12, 2015, 12:50:25 AM »
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The distance from the tip of Hayden to I5 is approx. 1.3 miles. the plane doesn't cross I5 until it's too late for the Smith lake landing. the distance from I5 to Smith lake is approx. 1.3 miles.

It's a possibility, but the odds are low if you go by the map. the black lines where made by the FBI, and the green is what Sluggo copied over if I'm correct.

If we go by Carr stating they claimed the bump was felt around 5-10 minutes after the last contact with Cooper which was 8:05. this gives a time frame of no later than 8:15.

No cars were left at any airports. I believe they covered that. we have no proof Cooper knew where he was. that's the difference between Cooper, and McCoy. Cooper never asked anything about altitude, wind, location, nothing. McCoy stayed on top of things like he was a co-pilot. 

The area in question is a National Preserve. one can expect people around often. if Cooper was at the bottom, or the money was at the bottom. I doubt the flooding would cause it to surface. odds are low again that it was lying around the area waiting to be moved by a flood?

Snowmmans map is direct lines connecting the waypoints, it is not the actual flightpath, it would have been smoother taking it closer to I5.. Was it close enough??? IDK we don't have data in between the waypoints. It looks real close. Smith Lake was intentionally flooded "closed" in the winter and released in the summer. It likely had the high water level in the winter, but I am trying to get info for '71. The Willamette slough flows in and out (controlled) or did. The lake edges are not really explorable by foot, it is a wetland/marsh explorable by canoe. The shoreline is really not well explored.. Anybody have a spare cadaver dog handy and a canoe,,, j/k

If a body did impact a marsh, I am sure it would be buried in the bottom. It isn't very deep. The rotting/movement or yearly flood/release process could loosen some money. About a 6 mile float to TBAR. YES, this is theoretical.. so far

video
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Are there any pilots that can comment on the potential flight path between those waypoints..

There was no reason for the flight path between the Toledo area to the DME point south of Portland being anything other than a straight line.  In order for the airliner to be at that DME point at 8:18 PM, it would have had to pass over Tina Bar approximately six minutes earlier or about 8:12 PM which is one of the predicted jump times.

Keep in mind that these times are given in whole minutes.  If more accurate times, such as those on the ATC transcripts were available, these times could be refined and stated in minutes and seconds thereby increasing the accuracy of the estimated aircraft positions.

Also remember that earlier versions of the Tina Bar area topographical maps described the area between the eastern shore of the Columbia River and the eastern shore of Caterpillar Island as "mud flats".  That area has now been dredged and a marina in located in it.
« Last Edit: January 12, 2015, 12:54:25 AM by Robert99 »
 

georger

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Re: Tina Bar Money Find
« Reply #530 on: January 12, 2015, 01:08:10 AM »
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The distance from the tip of Hayden to I5 is approx. 1.3 miles. the plane doesn't cross I5 until it's too late for the Smith lake landing. the distance from I5 to Smith lake is approx. 1.3 miles.

It's a possibility, but the odds are low if you go by the map. the black lines where made by the FBI, and the green is what Sluggo copied over if I'm correct.

If we go by Carr stating they claimed the bump was felt around 5-10 minutes after the last contact with Cooper which was 8:05. this gives a time frame of no later than 8:15.

No cars were left at any airports. I believe they covered that. we have no proof Cooper knew where he was. that's the difference between Cooper, and McCoy. Cooper never asked anything about altitude, wind, location, nothing. McCoy stayed on top of things like he was a co-pilot. 

The area in question is a National Preserve. one can expect people around often. if Cooper was at the bottom, or the money was at the bottom. I doubt the flooding would cause it to surface. odds are low again that it was lying around the area waiting to be moved by a flood?

Snowmmans map is direct lines connecting the waypoints, it is not the actual flightpath, it would have been smoother taking it closer to I5.. Was it close enough??? IDK we don't have data in between the waypoints. It looks real close. Smith Lake was intentionally flooded "closed" in the winter and released in the summer. It likely had the high water level in the winter, but I am trying to get info for '71. The Willamette slough flows in and out (controlled) or did. The lake edges are not really explorable by foot, it is a wetland/marsh explorable by canoe. The shoreline is really not well explored.. Anybody have a spare cadaver dog handy and a canoe,,, j/k

If a body did impact a marsh, I am sure it would be buried in the bottom. It isn't very deep. The rotting/movement or yearly flood/release process could loosen some money. About a 6 mile float to TBAR. YES, this is theoretical.. so far

video
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Are there any pilots that can comment on the potential flight path between those waypoints..

It would have been an area not searched or probably not even considered. If he augured in there 3 minutes later all there is is a few bubbles, potentially. The money and Cooper could sit there until as late as the end of the drought of '78 then with the heavy rains and flooding things are set lose to move ... but one attractive thing in this theory is a remote place right in the middle of an urban setting and a place where a body might auger in and not be noticed.

What happens to his chute?

 
 
 

georger

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Re: Tina Bar Money Find
« Reply #531 on: January 12, 2015, 01:11:38 AM »
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The distance from the tip of Hayden to I5 is approx. 1.3 miles. the plane doesn't cross I5 until it's too late for the Smith lake landing. the distance from I5 to Smith lake is approx. 1.3 miles.

It's a possibility, but the odds are low if you go by the map. the black lines where made by the FBI, and the green is what Sluggo copied over if I'm correct.

If we go by Carr stating they claimed the bump was felt around 5-10 minutes after the last contact with Cooper which was 8:05. this gives a time frame of no later than 8:15.

No cars were left at any airports. I believe they covered that. we have no proof Cooper knew where he was. that's the difference between Cooper, and McCoy. Cooper never asked anything about altitude, wind, location, nothing. McCoy stayed on top of things like he was a co-pilot. 

The area in question is a National Preserve. one can expect people around often. if Cooper was at the bottom, or the money was at the bottom. I doubt the flooding would cause it to surface. odds are low again that it was lying around the area waiting to be moved by a flood?

Snowmmans map is direct lines connecting the waypoints, it is not the actual flightpath, it would have been smoother taking it closer to I5.. Was it close enough??? IDK we don't have data in between the waypoints. It looks real close. Smith Lake was intentionally flooded "closed" in the winter and released in the summer. It likely had the high water level in the winter, but I am trying to get info for '71. The Willamette slough flows in and out (controlled) or did. The lake edges are not really explorable by foot, it is a wetland/marsh explorable by canoe. The shoreline is really not well explored.. Anybody have a spare cadaver dog handy and a canoe,,, j/k

If a body did impact a marsh, I am sure it would be buried in the bottom. It isn't very deep. The rotting/movement or yearly flood/release process could loosen some money. About a 6 mile float to TBAR. YES, this is theoretical.. so far

video
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Are there any pilots that can comment on the potential flight path between those waypoints..

There was no reason for the flight path between the Toledo area to the DME point south of Portland being anything other than a straight line.  In order for the airliner to be at that DME point at 8:18 PM, it would have had to pass over Tina Bar approximately six minutes earlier or about 8:12 PM which is one of the predicted jump times.

Keep in mind that these times are given in whole minutes.  If more accurate times, such as those on the ATC transcripts were available, these times could be refined and stated in minutes and seconds thereby increasing the accuracy of the estimated aircraft positions.

Also remember that earlier versions of the Tina Bar area topographical maps described the area between the eastern shore of the Columbia River and the eastern shore of Caterpillar Island as "mud flats".  That area has now been dredged and a marina in located in it.

and, if he augers in there it's a short travel distance for the money... which favors some money surviving to be found... with an uncomplicated flow scenario between two geographically proximate points.
« Last Edit: January 12, 2015, 01:15:33 AM by georger »
 

FLYJACK

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Re: Tina Bar Money Find
« Reply #532 on: January 12, 2015, 01:24:11 AM »
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The distance from the tip of Hayden to I5 is approx. 1.3 miles. the plane doesn't cross I5 until it's too late for the Smith lake landing. the distance from I5 to Smith lake is approx. 1.3 miles.

It's a possibility, but the odds are low if you go by the map. the black lines where made by the FBI, and the green is what Sluggo copied over if I'm correct.

If we go by Carr stating they claimed the bump was felt around 5-10 minutes after the last contact with Cooper which was 8:05. this gives a time frame of no later than 8:15.

No cars were left at any airports. I believe they covered that. we have no proof Cooper knew where he was. that's the difference between Cooper, and McCoy. Cooper never asked anything about altitude, wind, location, nothing. McCoy stayed on top of things like he was a co-pilot. 

The area in question is a National Preserve. one can expect people around often. if Cooper was at the bottom, or the money was at the bottom. I doubt the flooding would cause it to surface. odds are low again that it was lying around the area waiting to be moved by a flood?

Snowmmans map is direct lines connecting the waypoints, it is not the actual flightpath, it would have been smoother taking it closer to I5.. Was it close enough??? IDK we don't have data in between the waypoints. It looks real close. Smith Lake was intentionally flooded "closed" in the winter and released in the summer. It likely had the high water level in the winter, but I am trying to get info for '71. The Willamette slough flows in and out (controlled) or did. The lake edges are not really explorable by foot, it is a wetland/marsh explorable by canoe. The shoreline is really not well explored.. Anybody have a spare cadaver dog handy and a canoe,,, j/k

If a body did impact a marsh, I am sure it would be buried in the bottom. It isn't very deep. The rotting/movement or yearly flood/release process could loosen some money. About a 6 mile float to TBAR. YES, this is theoretical.. so far

video
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Are there any pilots that can comment on the potential flight path between those waypoints..

It would have been an area not searched or probably not even considered. If he augured in there 3 minutes later all there is is a few bubbles, potentially. The money and Cooper could sit there until as late as the end of the drought of '78 then with the heavy rains and flooding things are set lose to move ... but one attractive thing in this theory is a remote place right in the middle of an urban setting and a place where a body might auger in and not be noticed.

What happens to his chute?



hey, I am still trying to figure out IF he could have landed there,, :o

There was work done in there over the years and the two lakes are connected to the rivers affected by tides and river levels, a direct float to TBAR is possible,

That lake isn't very deep, more like a marsh,  an impact might bury a body and unopened chute many feet into the bottom. There was some dredging dumped into it, as well as channels made.. but hard to really pin down levels and work timelines.

more general info,,

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georger

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Re: Tina Bar Money Find
« Reply #533 on: January 12, 2015, 05:51:47 AM »
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The distance from the tip of Hayden to I5 is approx. 1.3 miles. the plane doesn't cross I5 until it's too late for the Smith lake landing. the distance from I5 to Smith lake is approx. 1.3 miles.

It's a possibility, but the odds are low if you go by the map. the black lines where made by the FBI, and the green is what Sluggo copied over if I'm correct.

If we go by Carr stating they claimed the bump was felt around 5-10 minutes after the last contact with Cooper which was 8:05. this gives a time frame of no later than 8:15.

No cars were left at any airports. I believe they covered that. we have no proof Cooper knew where he was. that's the difference between Cooper, and McCoy. Cooper never asked anything about altitude, wind, location, nothing. McCoy stayed on top of things like he was a co-pilot. 

The area in question is a National Preserve. one can expect people around often. if Cooper was at the bottom, or the money was at the bottom. I doubt the flooding would cause it to surface. odds are low again that it was lying around the area waiting to be moved by a flood?

Snowmmans map is direct lines connecting the waypoints, it is not the actual flightpath, it would have been smoother taking it closer to I5.. Was it close enough??? IDK we don't have data in between the waypoints. It looks real close. Smith Lake was intentionally flooded "closed" in the winter and released in the summer. It likely had the high water level in the winter, but I am trying to get info for '71. The Willamette slough flows in and out (controlled) or did. The lake edges are not really explorable by foot, it is a wetland/marsh explorable by canoe. The shoreline is really not well explored.. Anybody have a spare cadaver dog handy and a canoe,,, j/k

If a body did impact a marsh, I am sure it would be buried in the bottom. It isn't very deep. The rotting/movement or yearly flood/release process could loosen some money. About a 6 mile float to TBAR. YES, this is theoretical.. so far

video
You are not allowed to view links. Register or Login

Are there any pilots that can comment on the potential flight path between those waypoints..

It would have been an area not searched or probably not even considered. If he augured in there 3 minutes later all there is is a few bubbles, potentially. The money and Cooper could sit there until as late as the end of the drought of '78 then with the heavy rains and flooding things are set lose to move ... but one attractive thing in this theory is a remote place right in the middle of an urban setting and a place where a body might auger in and not be noticed.

What happens to his chute?



hey, I am still trying to figure out IF he could have landed there,, :o

There was work done in there over the years and the two lakes are connected to the rivers affected by tides and river levels, a direct float to TBAR is possible,

That lake isn't very deep, more like a marsh,  an impact might bury a body and unopened chute many feet into the bottom. There was some dredging dumped into it, as well as channels made.. but hard to really pin down levels and work timelines.

more general info,,

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no problem - no pressure here. It's an interesting idea and related to other critical issues and interesting options, all worthy of discussion. So no pressure here of any kind. Im all ears... as you said it's a fresh idea and I now see where you're going....

Dont anyone ever get the idea, ideas need my approval here or that I think that, because I don't think that and they don't need my approval in any event, in case I need to say this.  ;)   


« Last Edit: January 12, 2015, 06:01:04 AM by georger »
 

FLYJACK

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Re: Tina Bar Money Find
« Reply #534 on: January 12, 2015, 09:47:48 AM »
My maths was wrong when I upped the speed to 170k per the cockpit communications. I forgot to update the m/sec

use this to get t for 10000, 170k and 200lbs = 26.3 seconds in the air
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convert 170k to m/sec = 87.5 m/sec
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speed * time = distance

87.5 m/sec * 26.3 = 2301 meters or 1.43 miles forward distance from drop in a no pull (assume estimation +/-)

Lets try Occams razor.. simplest assumptions

The bump felt was the stairs dropping.
The initial FBI flight path drawn in BLACK is correct
He left the plane over Hayden Island near I5
He travelled forward approximately 1.43 miles (2300 m) to the NorthEast area of Smith Lake (2100 m I5 on Hayden to Smith Lake)
He died on impact in a no pull
He disappears embedded deep into the marshy bottom, winter is high water level but the lake is very shallow
The river tides (affect lake), body decomposition, yearly flooding or work loosens some money years later
It is a 6-7 mile waterway float downstream to TBAR

AND, it seems nobody has looked, he might still be there

This relies on the flightpath.

"Speculation warning" If the black pen FBI flightpath is correct and there was a slight South turn over Hayden, he may have been jarred from the stairs. If he was at the end of the stairs looking for ground markers and the plane turned, he may have lost his grip and got tossed off prior to his intended LZ.

That area of the Lake/marsh is really only accessible by canoe,,,

Cadaver dogs can detect 15 feet underground and a 100 year old body.. (not referring to Jo)

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Tom Osterkamp,1,2 Ph.D.
K9 Water Searches: Scent and ScentTransport Considerations

"Consideration of training aids that dogs are known to detect can aid in the identification of potential scent sources from a sub- merged body. Dogs can detect submerged clothing and shoes (7), possibly from VOCs in the items as a result of contact with the skin. Some handlers use human hair that is normally covered with glandular secretions as a training aid. Fingerprints consist of water, soluble compounds, and insoluble compounds modified by hydrolysis and bacterial degradation that include VOCs that have been impli- cated in human scent (14,16). A single fingerprint on a slide immersed in water produced an oil film on the water surface within a few minutes (27) although the transport process remains unknown. Human bones produce VOCs (20) and have been used as training aids that are detectable by water search dogs."

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« Last Edit: January 12, 2015, 01:12:06 PM by FLYJACK »
 

Robert99

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Re: Tina Bar Money Find
« Reply #535 on: January 12, 2015, 01:23:39 PM »
Flyjack,

Have you ever noticed that physics books ignore the atmosphere when discussing such things as bombs being dropped from aircraft, artillery fire, and everything else that involves horizontal motion in the atmosphere?  And that these same books include the atmosphere when they discuss only vertical motion in the atmosphere.

The reason for the above is that vertical motion only is easily handled mathematically by a slide rule or by hand.  But adding ANY horizontal motion to the problem produces a fourth-order quadratic equation (or some such thing) that requires something such as a Cray Supercomputer to produce meaningful results.

For parachutists, jumping from about 10,000 feet and at about 225 MPH (195 Knots) as Cooper did, the rule of thumb for a falling body (unopened parachute) is that all forward motion will be cancelled out after about 1250 feet of forward travel.  Then the body will fall vertically but will be influenced by any horizontal wind that exists.

If a parachutist descends from 10,000 feet in a stable "skydiver horizontal spread" without opening his parachute, he will be on the ground (and dead) in about 60 seconds.  His speed at ground contact would be about 120 MPH.

If a parachutist descends from 10,000 feet in a stable head-straight-down position without opening his parachute, he will be on the ground (and dead) in about 40 seconds or less.  His speed at ground contact would be about 180+ MPH.

Back about 2009, I did some calculations about what would happen to Cooper's aerodynamics when he tied the money bag to himself.  Basically, the volume and weight of the money bag, plus other things Cooper had (such as his raincoat), would balance each other to keep his speed in a head first straight down fall to about the 180+ MPH mentioned above.  And Cooper's "configuration" would probably stabilize him in a head first fall.

So Cooper had about 40 seconds at most from the time he separated from the stairs to open his parachute.  There is no evidence that he did so.  This was probably Cooper's first actual jump and all of the events probably caused him to become disoriented and he lost track of time.  If Cooper was a no-pull, the canopy is probably still in the pack.

Further, if you have access to a Cray Supercomputer, preferably more than one, and a staff of programmers and operators to run it, plus someone to pay the bills, please PM me as fast as possible.

Robert99
« Last Edit: January 12, 2015, 01:26:46 PM by Robert99 »
 

FLYJACK

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Re: Tina Bar Money Find
« Reply #536 on: January 12, 2015, 01:51:16 PM »
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Flyjack,

Have you ever noticed that physics books ignore the atmosphere when discussing such things as bombs being dropped from aircraft, artillery fire, and everything else that involves horizontal motion in the atmosphere?  And that these same books include the atmosphere when they discuss only vertical motion in the atmosphere.

The reason for the above is that vertical motion only is easily handled mathematically by a slide rule or by hand.  But adding ANY horizontal motion to the problem produces a fourth-order quadratic equation (or some such thing) that requires something such as a Cray Supercomputer to produce meaningful results.

For parachutists, jumping from about 10,000 feet and at about 225 MPH (195 Knots) as Cooper did, the rule of thumb for a falling body (unopened parachute) is that all forward motion will be cancelled out after about 1250 feet of forward travel.  Then the body will fall vertically but will be influenced by any horizontal wind that exists.

If a parachutist descends from 10,000 feet in a stable "skydiver horizontal spread" without opening his parachute, he will be on the ground (and dead) in about 60 seconds.  His speed at ground contact would be about 120 MPH.

If a parachutist descends from 10,000 feet in a stable head-straight-down position without opening his parachute, he will be on the ground (and dead) in about 40 seconds or less.  His speed at ground contact would be about 180+ MPH.

Back about 2009, I did some calculations about what would happen to Cooper's aerodynamics when he tied the money bag to himself.  Basically, the volume and weight of the money bag, plus other things Cooper had (such as his raincoat), would balance each other to keep his speed in a head first straight down fall to about the 180+ MPH mentioned above.  And Cooper's "configuration" would probably stabilize him in a head first fall.

So Cooper had about 40 seconds at most from the time he separated from the stairs to open his parachute.  There is no evidence that he did so.  This was probably Cooper's first actual jump and all of the events probably caused him to become disoriented and he lost track of time.  If Cooper was a no-pull, the canopy is probably still in the pack.

Further, if you have access to a Cray Supercomputer, preferably more than one, and a staff of programmers and operators to run it, plus someone to pay the bills, please PM me as fast as possible.

Robert99

Yes, I agree, I found this out when trying to find a formula.. it gets extremely complex with the variables, known and unknown. I tried to be conservative with the calculation.

The purpose was not really "precision" but a probability that he could have landed in Smith Lake given the FBI flightpath, if 26.3 sec flight time is a conservative lower bound and you found 40 sec as a possible upper bound, that is 1.4 to 2.17 miles forward travel making it possible for him to land in Smith Lake using the original FBI flightpath over Hayden..  What really makes this "theory" interesting is that there could be something still there unlike a landing in the Columbia and it isn't expensive to run a cadaver dog or sonar over that area.

Though, I used 170 knots per the crew communication, not 195..
« Last Edit: January 12, 2015, 02:30:42 PM by FLYJACK »
 

Robert99

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Re: Tina Bar Money Find
« Reply #537 on: January 12, 2015, 02:33:35 PM »
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Flyjack,

Have you ever noticed that physics books ignore the atmosphere when discussing such things as bombs being dropped from aircraft, artillery fire, and everything else that involves horizontal motion in the atmosphere?  And that these same books include the atmosphere when they discuss only vertical motion in the atmosphere.

The reason for the above is that vertical motion only is easily handled mathematically by a slide rule or by hand.  But adding ANY horizontal motion to the problem produces a fourth-order quadratic equation (or some such thing) that requires something such as a Cray Supercomputer to produce meaningful results.

For parachutists, jumping from about 10,000 feet and at about 225 MPH (195 Knots) as Cooper did, the rule of thumb for a falling body (unopened parachute) is that all forward motion will be cancelled out after about 1250 feet of forward travel.  Then the body will fall vertically but will be influenced by any horizontal wind that exists.

If a parachutist descends from 10,000 feet in a stable "skydiver horizontal spread" without opening his parachute, he will be on the ground (and dead) in about 60 seconds.  His speed at ground contact would be about 120 MPH.

If a parachutist descends from 10,000 feet in a stable head-straight-down position without opening his parachute, he will be on the ground (and dead) in about 40 seconds or less.  His speed at ground contact would be about 180+ MPH.

Back about 2009, I did some calculations about what would happen to Cooper's aerodynamics when he tied the money bag to himself.  Basically, the volume and weight of the money bag, plus other things Cooper had (such as his raincoat), would balance each other to keep his speed in a head first straight down fall to about the 180+ MPH mentioned above.  And Cooper's "configuration" would probably stabilize him in a head first fall.

So Cooper had about 40 seconds at most from the time he separated from the stairs to open his parachute.  There is no evidence that he did so.  This was probably Cooper's first actual jump and all of the events probably caused him to become disoriented and he lost track of time.  If Cooper was a no-pull, the canopy is probably still in the pack.

Further, if you have access to a Cray Supercomputer, preferably more than one, and a staff of programmers and operators to run it, plus someone to pay the bills, please PM me as fast as possible.

Robert99

Yes, I agree, I found this out when trying to find a formula.. it gets extremely complex with the variables, known and unknown. I tried to be conservative with the calculation.

The purpose was not really "precision" but a probability that he could have landed in Smith Lake given the FBI flightpath, if 26.3 sec flight time is a conservative lower bound and you found 40 sec as a possible upper bound, that is 1.4 to 2.17 miles forward travel making it possible for him to land in Smith Lake using the original FBI flightpath over Hayden..  What really makes this "theory" interesting is that there could be something still there unlike a landing in the Columbia and it isn't expensive to run a cadaver dog over that area.

Though, I used 170 knots per the crew communication, not 195..

Flyjack, The 170 Knots mentioned by the crew is what they see on their cockpit instruments.  The 195 Knots is the true airspeed of the aircraft with respect to the atmosphere.  If there were no winds, then that 195 Knots would also be the speed over the ground.  But the ground speed is going to be less than that by the amount of the headwind component from the winds aloft.  The winds aloft were roughly 30 knots from the southwest and the airliner was heading 178 degrees or almost straight south.  That produces a headwind component for the airliner of about 15 to 20 knots which must be deducted from the 195 knots true airspeed to give the speed of the airliner over the ground.

I apparently didn't get the point across about the distance Cooper would have travelled down track when he separated from the airliner.  That distance would not be more than about 1250 feet under the known jump conditions.  And he would have been blown slightly towards the northeast by the winds aloft.  Assuming that Cooper would have been blown about 1000 feet to the northeast by the winds (about 10 knots at ground level and about 30 knots at 10,000 feet), in order for him to impact as a no-pull at the money find location at Tina Bar, he would have to separate from the airliner about 1250 feet North of Tina Bar and essentially over the western edge of the Columbia River (which runs North and South at Tina Bar).

To repeat, assuming a no-pull situation, Cooper's forward motion down the airliner's track would be reduced to zero within about 1250 feet (with respect to the air mass), and his descent would be straight down thereafter except as influenced by the winds aloft which would blow him slightly to the northeast.
 

georger

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Re: Tina Bar Money Find
« Reply #538 on: January 12, 2015, 02:54:40 PM »
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Flyjack,

Have you ever noticed that physics books ignore the atmosphere when discussing such things as bombs being dropped from aircraft, artillery fire, and everything else that involves horizontal motion in the atmosphere?  And that these same books include the atmosphere when they discuss only vertical motion in the atmosphere.

The reason for the above is that vertical motion only is easily handled mathematically by a slide rule or by hand.  But adding ANY horizontal motion to the problem produces a fourth-order quadratic equation (or some such thing) that requires something such as a Cray Supercomputer to produce meaningful results.

For parachutists, jumping from about 10,000 feet and at about 225 MPH (195 Knots) as Cooper did, the rule of thumb for a falling body (unopened parachute) is that all forward motion will be cancelled out after about 1250 feet of forward travel.  Then the body will fall vertically but will be influenced by any horizontal wind that exists.

If a parachutist descends from 10,000 feet in a stable "skydiver horizontal spread" without opening his parachute, he will be on the ground (and dead) in about 60 seconds.  His speed at ground contact would be about 120 MPH.

If a parachutist descends from 10,000 feet in a stable head-straight-down position without opening his parachute, he will be on the ground (and dead) in about 40 seconds or less.  His speed at ground contact would be about 180+ MPH.

Back about 2009, I did some calculations about what would happen to Cooper's aerodynamics when he tied the money bag to himself.  Basically, the volume and weight of the money bag, plus other things Cooper had (such as his raincoat), would balance each other to keep his speed in a head first straight down fall to about the 180+ MPH mentioned above.  And Cooper's "configuration" would probably stabilize him in a head first fall.

So Cooper had about 40 seconds at most from the time he separated from the stairs to open his parachute.  There is no evidence that he did so.  This was probably Cooper's first actual jump and all of the events probably caused him to become disoriented and he lost track of time.  If Cooper was a no-pull, the canopy is probably still in the pack.

Further, if you have access to a Cray Supercomputer, preferably more than one, and a staff of programmers and operators to run it, plus someone to pay the bills, please PM me as fast as possible.

Robert99

Yes, I agree, I found this out when trying to find a formula.. it gets extremely complex with the variables, known and unknown. I tried to be conservative with the calculation.

The purpose was not really "precision" but a probability that he could have landed in Smith Lake given the FBI flightpath, if 26.3 sec flight time is a conservative lower bound and you found 40 sec as a possible upper bound, that is 1.4 to 2.17 miles forward travel making it possible for him to land in Smith Lake using the original FBI flightpath over Hayden..  What really makes this "theory" interesting is that there could be something still there unlike a landing in the Columbia and it isn't expensive to run a cadaver dog or sonar over that area.

Though, I used 170 knots per the crew communication, not 195..

Im not sure about your '1.4 to 2.17 miles forward travel'.  The skydivers at DZ used 1200 feet (forward throw).
???

Quoted from R99's above: "To repeat, assuming a no-pull situation, Cooper's forward motion down the airliner's track would be reduced to zero within about 1250 feet (with respect to the air mass), and his descent would be straight down (actually parabolic) thereafter except as influenced by the winds aloft which would blow him slightly to the northeast."

A no-pull would account for no parachute seen. However, let's assume he does get the chute open and still lands in this area (extended timeline allowing) - he is still is potentially in a 'sticky' situation ... up to his ass in marsh!   He might have had to separate himself from the money container to get himself out? Or, lets assume a partial chute opening - that scenario is a virtual no-pull at a slower velocity but he is still up to his neck in muck ... and maybe injured or dead.
 
« Last Edit: January 12, 2015, 03:35:28 PM by georger »
 

FLYJACK

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Re: Tina Bar Money Find
« Reply #539 on: January 12, 2015, 04:31:46 PM »
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Flyjack,

Have you ever noticed that physics books ignore the atmosphere when discussing such things as bombs being dropped from aircraft, artillery fire, and everything else that involves horizontal motion in the atmosphere?  And that these same books include the atmosphere when they discuss only vertical motion in the atmosphere.

The reason for the above is that vertical motion only is easily handled mathematically by a slide rule or by hand.  But adding ANY horizontal motion to the problem produces a fourth-order quadratic equation (or some such thing) that requires something such as a Cray Supercomputer to produce meaningful results.

For parachutists, jumping from about 10,000 feet and at about 225 MPH (195 Knots) as Cooper did, the rule of thumb for a falling body (unopened parachute) is that all forward motion will be cancelled out after about 1250 feet of forward travel.  Then the body will fall vertically but will be influenced by any horizontal wind that exists.

If a parachutist descends from 10,000 feet in a stable "skydiver horizontal spread" without opening his parachute, he will be on the ground (and dead) in about 60 seconds.  His speed at ground contact would be about 120 MPH.

If a parachutist descends from 10,000 feet in a stable head-straight-down position without opening his parachute, he will be on the ground (and dead) in about 40 seconds or less.  His speed at ground contact would be about 180+ MPH.

Back about 2009, I did some calculations about what would happen to Cooper's aerodynamics when he tied the money bag to himself.  Basically, the volume and weight of the money bag, plus other things Cooper had (such as his raincoat), would balance each other to keep his speed in a head first straight down fall to about the 180+ MPH mentioned above.  And Cooper's "configuration" would probably stabilize him in a head first fall.

So Cooper had about 40 seconds at most from the time he separated from the stairs to open his parachute.  There is no evidence that he did so.  This was probably Cooper's first actual jump and all of the events probably caused him to become disoriented and he lost track of time.  If Cooper was a no-pull, the canopy is probably still in the pack.

Further, if you have access to a Cray Supercomputer, preferably more than one, and a staff of programmers and operators to run it, plus someone to pay the bills, please PM me as fast as possible.

Robert99

Yes, I agree, I found this out when trying to find a formula.. it gets extremely complex with the variables, known and unknown. I tried to be conservative with the calculation.

The purpose was not really "precision" but a probability that he could have landed in Smith Lake given the FBI flightpath, if 26.3 sec flight time is a conservative lower bound and you found 40 sec as a possible upper bound, that is 1.4 to 2.17 miles forward travel making it possible for him to land in Smith Lake using the original FBI flightpath over Hayden..  What really makes this "theory" interesting is that there could be something still there unlike a landing in the Columbia and it isn't expensive to run a cadaver dog or sonar over that area.

Though, I used 170 knots per the crew communication, not 195..

Im not sure about your '1.4 to 2.17 miles forward travel'.  The skydivers at DZ used 1200 feet (forward throw).
???

Quoted from R99's above: "To repeat, assuming a no-pull situation, Cooper's forward motion down the airliner's track would be reduced to zero within about 1250 feet (with respect to the air mass), and his descent would be straight down (actually parabolic) thereafter except as influenced by the winds aloft which would blow him slightly to the northeast."

A no-pull would account for no parachute seen. However, let's assume he does get the chute open and still lands in this area (extended timeline allowing) - he is still is potentially in a 'sticky' situation ... up to his ass in marsh!   He might have had to separate himself from the money container to get himself out? Or, lets assume a partial chute opening - that scenario is a virtual no-pull at a slower velocity but he is still up to his neck in muck ... and maybe injured or dead.

I calculated 1.4 miles for an "object", that jives with other calculations and tables for projectile motion dropped from a plane, but I did find the skydiver rule of thumb that forward throw =  4 x m/sec, that would be about 400m, far shorter. Though a head down might increase that, still nowhere close. Why such a difference?? attributed to drag alone?? I'll have to look into it more.

hard to see a pulled chute going unnoticed,