Another reference to about 3 feet per second.

"Relevant Fact— The placard was found about 13 miles east of Castle Rock. This is  commensurate with the strong winds from the west. Its rate of fall would usually be around 2.5 feet per second. Put all the calculations together and it would drop about 9000 feet in an hour. Add the heavier weather, barometric pressure, and the intermittent downpour, and the rate of decent is doubled. Thus the placard could have been found as much as 22 miles or more east of where it dropped from the Boeing 727."




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Yes.

“We took the Cooper plane up after the hijacking and simulated a drop by a parachutist,’’ he said.. “We noticed the decal was missing after that but not before.� See page seven (7).
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That would account for no mention of the placard being missing at Reno or elsewhere. Any photos from the TAG team test that show the placard is still in the plane post-hijacking?

In addition several others are challenging the terminal-v assignment by R99 and Ulis. Two #s produced:

3 ft/sec = 180ft/min falling 8680 ft = 48 minutes
2 ft/sec = 120 ft/min falling 8680 ft = 72 minutes

You can read it on DZ.

I see nobody bothered to comment about the 727 turbulence videos I posted. So be it. It will come up again ... and again .... and again ....

Go back to the Colbert program video showing Eng packing up evidence to be shipped to Washington DC, as part of the case closing. Is the 727 placard shown?

Good night Elvis, wherever you are! 

The PDF is outstanding. So this is where our tax dollars go?

This proves that the placard didn't descend straight down or into a 31 KT wind. Not that I need anyone to prove it to me. It's just ridiculous to consider and is a waste of time to discuss further.

The question then becomes: How far did the placard drift?

To suggest a 3 ft/sec rate is wrong. As noted above, the placard is more than double the weight of the leaflet and has 1/4th of the surface.

The larger point, and only point that needs to be made, is that the placard find spot points to a flight path several miles west of the FBI Flight Path at that point.

In lieu of:

1) Significant placard migration on the ground to the west, or...

2) Proving that by some hard-to-quantify coincidence the placard dislodged from another 727 in the area, or...

3) The placard dislodged from N467US during testing (which would require the airstairs to be deployed over land), or...

4) This was a "special weather zone,"...

there is a major problem here. The FBI Flight Path cannot be accurate at that point. Moreover, it points to an actual flight path several miles to the west.

Flyjack originally posted the 3 foot drop. It's based on a larger leaflet. The smaller ones don't seem to change much. However, this appears to be the data needed. This will not prove much since we have a seven year gap. What if it show 15 mile drift? Do you move the path 15 miles?

Another site also quoted a 2-3 foot drop. How they figured that. I haven't a clue. I only posted what I seen.

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Flyjack originally posted the 3 foot drop. It's based on a larger leaflet. The smaller ones don't seem to change much. However, this appears to be the data needed. This will not prove much since we have a seven year gap. What if it show 15 mile drift? Do you move the path 15 miles?

Another site also quoted a 2-3 foot drop. How they figured that. I haven't a clue. I only posted what I seen.

What I posted has nothing to do with FJ and any calcs he did ... like I just said, go with the pdf values you have.

I never said it did? I responded to Roberts question of where the figures came from!

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Flyjack originally posted the 3 foot drop. It's based on a larger leaflet. The smaller ones don't seem to change much. However, this appears to be the data needed. This will not prove much since we have a seven year gap. What if it show 15 mile drift? Do you move the path 15 miles?

Another site also quoted a 2-3 foot drop. How they figured that. I haven't a clue. I only posted what I seen.

What I posted has nothing to do with FJ and any calcs he did ... like I just said, go with the pdf values you have.

I never said it did? I responded to Roberts question of where the figures came from!

I removed the offending posts! 

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Flyjack originally posted the 3 foot drop. It's based on a larger leaflet. The smaller ones don't seem to change much. However, this appears to be the data needed. This will not prove much since we have a seven year gap. What if it show 15 mile drift? Do you move the path 15 miles?

Another site also quoted a 2-3 foot drop. How they figured that. I haven't a clue. I only posted what I seen.

What I posted has nothing to do with FJ and any calcs he did ... like I just said, go with the pdf values you have.

I never said it did? I responded to Roberts question of where the figures came from!

I removed the offending posts! 

Georger,

I never saw the post you are apparently referring to so I don't know what you were saying in the first place.  I did take a look at the CIA report that Shutter posted and I would suggest that you do the same and specifically take a look at Table NA-3 on page 27.

Find the line that lists the ground rate of descent for 3.0 feet per second.  Read across that line until you come to the entry for 10,000 feet altitude.  That entry lists a time of 0.13 hours, which is 7.80 minutes, for a non-rotating placard to reach the ground from 10,000 feet.  That is an average rate of descent of 1282 feet per minute which is about the same rate of descent as a round 1971 era parachute with a 200 pound load.

Things get worse.  Look again at that 3.0 ground rate of descent.  And note that it supposedly takes 0.03 hours, which is 1.8 minutes, to go from 0 altitude to ground level which is the same thing.  I look forward to seeing your explanation of how that happens!  I didn't bother reading further in that report.

I see nothing in that report that would support the FBI flight path.   

Thats actually funny Rebert! I see nothing in that report that would support the FBI flight path, either. That report was not written to support or not support the FBI flight path.    Now you really are looking for Jesus in the Toast. But, is the toast looking to be saved?

I think I will start ignoring your egotistical venom. Bye!  Maybe its you who needs to do some reading for a change ?

As I recall this, you spent years at Dropzone claiming the money arrived on Tina Bar, from the south end of TBar. Your old posts are still at DZ. You spent months/years trying to locate a creek or channel that could feed the money "slowly you said" to the south end of Tina Bar. You thought a west path could accommodate that. That was the basis for your earliest west path, as I recall this. Maybe now you will call me a liar about that!

Then when you joined forces with Elvis/Ulis your west path morphed. It now favored a more northern intersection with TBar to accommodate Ulis' claim that that the Ingram find is where DB Cooper (Sheridan Peterson) buried the money on Tina Bar.

The upshot of all this and what disturbs me is that you seem to be willing to shift your flight paths around to accommodate the latest-greatest theory being published in the "news".  You and Ulis now use the placard to justify all of this. If what you claim this month is true why the change? Why didn't you pin your west path on the placard all along - clear back in 2008? In contrast the FBI etal have not changed their basic flight path in what, 40+ years! I mean compared to you the FBI seems to be less subject to the whims of change and the latest-greatest broadcaster in the Cooper Forum News cycle.

In the final analysis it is what it is. Maybe it will change again tomorrow for some reason.

Thanks and take care.     

That chart doesn't seem to make sense. it continues with altitudes in the next figures directly below showing the last altitude of 50,000.
3.0 ft/sec at 50k takes .05?

.09 at 1,000 feet?

The figures remain the same for altitudes of 1,000 thru 9,000 feet?

Are these figures something to factor in with other figures vs what the actual number or conclusion is for these altitudes?

Three feet a second would be 180 feet per minute. not 700 feet as you calculated being similar to a parachute drift. how do they equal?

The chart is for non-rotation which appears to have changed from it "tumbling"

Chart below is just an example...

The chart you have posted shows various data for each altitude segment.

For example, if you drop leaflets at 1000 feet the data pertaining to that segment would be in the "5-0 height increment." Next, for a leaflet to travel through that entire segment--meaning 5k to 0 feet--it would take 0.49 hours. However, your placard drop would be only from 1K. Therefore it would take about 1/5th of the time, in other words, 0.9 hours. Moreover, the wind speed is 5 KTS during that segment, you would have a horizontal drift of 1/5th of 2.5 NM, and the azimuth angle is 170.